What are the solutions to the equation a=x^2-4x+1 ?

The solutions to the equation a=x^2-4x+1 are x=2+sqrt(a+3),x=2-sqrt(a+3)

Find the zeros of a=x^2-4x+1

The zeros of a=x^2-4x+1 are x=2+sqrt(a+3),x=2-sqrt(a+3)

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a = x^{2} - 4 x + 1

x = 2 + a + 3, x = 2 - a + 3

Solution steps

a = x^{2} - 4 x + 1

Switch sides

x^{2} - 4 x + 1 = a

Move

a

to the left side

x^{2} - 4 x + 1 - a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( 1 - a )}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot (1 - a) : 2 a + 3

x_{1, 2} = \frac{- ( - 4 ) \pm 2 a + 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 a + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 a + 3}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 a + 3}{2 \cdot 1} : 2 + a + 3

x = \frac{- ( - 4 ) - 2 a + 3}{2 \cdot 1} : 2 - a + 3

The solutions to the quadratic equation are:

x = 2 + a + 3, x = 2 - a + 3

e = m^{0} \frac{c ^{2}}{1} - \frac{v ^{2}}{c ^{2}}

(t) = - t^{2} + 22 t - 85

x, a = (x - 5)^{2} + 5 y^{6} - 30

\frac{2 x ^{2}}{3} = 32

3 x^{2} + 25 x - 5 = 0

What are the solutions to the equation a=x^2-4x+1 ?
The solutions to the equation a=x^2-4x+1 are x=2+sqrt(a+3),x=2-sqrt(a+3)
Find the zeros of a=x^2-4x+1
The zeros of a=x^2-4x+1 are x=2+sqrt(a+3),x=2-sqrt(a+3)