What are the solutions to the equation 6m^2+4m=3 ?

The solutions to the equation 6m^2+4m=3 are m=(-2+sqrt(22))/6 ,m=-(2+sqrt(22))/6

Find the zeros of 6m^2+4m=3

The zeros of 6m^2+4m=3 are m=(-2+sqrt(22))/6 ,m=-(2+sqrt(22))/6

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6 m^{2} + 4 m = 3

m = \frac{- 2 + 22}{6}, m = - \frac{2 + 22}{6}

Decimal Notation

m = 0.44840 \dots, m = - 1.11506 \dots

Solution steps

6 m^{2} + 4 m = 3

Move

3

to the left side

6 m^{2} + 4 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

4^{2} - 4 \cdot 6 (- 3) = 222

m_{1, 2} = \frac{- 4 \pm 2 22}{2 \cdot 6}

Separate the solutions

m_{1} = \frac{- 4 + 2 22}{2 \cdot 6}, m_{2} = \frac{- 4 - 2 22}{2 \cdot 6}

m = \frac{- 4 + 2 22}{2 \cdot 6} : \frac{- 2 + 22}{6}

m = \frac{- 4 - 2 22}{2 \cdot 6} : - \frac{2 + 22}{6}

The solutions to the quadratic equation are:

m = \frac{- 2 + 22}{6}, m = - \frac{2 + 22}{6}

x, y^{2} - x^{2} = a

(\frac{+ v}{2})^{2} = (+ v)^{2} + 2 (- g) (+ 30)

a^{2} - 256 - 15 = 0

(x - 5) (2 x + 5) = 0

x^{2} + 9 x - 3 b = 0

What are the solutions to the equation 6m^2+4m=3 ?
The solutions to the equation 6m^2+4m=3 are m=(-2+sqrt(22))/6 ,m=-(2+sqrt(22))/6
Find the zeros of 6m^2+4m=3
The zeros of 6m^2+4m=3 are m=(-2+sqrt(22))/6 ,m=-(2+sqrt(22))/6