What are the solutions to the equation 109x^2-3x-2=0 ?

The solutions to the equation 109x^2-3x-2=0 are x=(3+sqrt(881))/(218),x=(3-sqrt(881))/(218)

Find the zeros of 109x^2-3x-2=0

The zeros of 109x^2-3x-2=0 are x=(3+sqrt(881))/(218),x=(3-sqrt(881))/(218)

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109 x^{2} - 3 x - 2 = 0

x = \frac{3 + 881}{218}, x = \frac{3 - 881}{218}

Decimal Notation

x = 0.14991 \dots, x = - 0.12239 \dots

Solution steps

109 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 109 ( - 2 )}{2 \cdot 109}

(- 3)^{2} - 4 \cdot 109 (- 2) = 881

x_{1, 2} = \frac{- ( - 3 ) \pm 881}{2 \cdot 109}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 881}{2 \cdot 109}, x_{2} = \frac{- ( - 3 ) - 881}{2 \cdot 109}

x = \frac{- ( - 3 ) + 881}{2 \cdot 109} : \frac{3 + 881}{218}

x = \frac{- ( - 3 ) - 881}{2 \cdot 109} : \frac{3 - 881}{218}

The solutions to the quadratic equation are:

x = \frac{3 + 881}{218}, x = \frac{3 - 881}{218}

x, x^{2} + y^{2} - 6 x + 6 y + 18 = 0

x = 5 x - 4 x^{2} + 3

x^{2} + (m + 3) \cdot x + (m + 6) = 0

x, (y - 3 x) (x - 8 y) = 0

x, z = 3 \cdot x^{2} - x \cdot y^{2}

What are the solutions to the equation 109x^2-3x-2=0 ?
The solutions to the equation 109x^2-3x-2=0 are x=(3+sqrt(881))/(218),x=(3-sqrt(881))/(218)
Find the zeros of 109x^2-3x-2=0
The zeros of 109x^2-3x-2=0 are x=(3+sqrt(881))/(218),x=(3-sqrt(881))/(218)