What are the solutions to the equation (d^3-3d-2)=x^2 ?

The solutions to the equation (d^3-3d-2)=x^2 are x=(d+1)sqrt(d-2),x=-(d+1)sqrt(d-2)

Find the zeros of (d^3-3d-2)=x^2

The zeros of (d^3-3d-2)=x^2 are x=(d+1)sqrt(d-2),x=-(d+1)sqrt(d-2)

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(d^{3} - 3 d - 2) = x^{2}

x = (d + 1) d - 2, x = - (d + 1) d - 2

Solution steps

(d^{3} - 3 d - 2) = x^{2}

Switch sides

x^{2} = (d^{3} - 3 d - 2)

Remove parentheses:

(a) = a

x^{2} = d^{3} - 3 d - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = d^{3} - 3 d - 2, x = - d^{3} - 3 d - 2

Simplify

d^{3} - 3 d - 2 : (d + 1) d - 2

Simplify

- d^{3} - 3 d - 2 : - (d + 1) d - 2

x = (d + 1) d - 2, x = - (d + 1) d - 2

14 x^{1} - 3 x^{2} = 8, x^{1} + 5 x^{2} = 11

y, y^{2} = x (x^{2} - 3)

a^{2} b^{2} x^{2} + b^{2} x - a^{2} x - 1 = 0

100 t^{2} - 192 t + 256 = 0

\frac{a}{b} = k^{2}

What are the solutions to the equation (d^3-3d-2)=x^2 ?
The solutions to the equation (d^3-3d-2)=x^2 are x=(d+1)sqrt(d-2),x=-(d+1)sqrt(d-2)
Find the zeros of (d^3-3d-2)=x^2
The zeros of (d^3-3d-2)=x^2 are x=(d+1)sqrt(d-2),x=-(d+1)sqrt(d-2)