What are the solutions to the equation (x-2)*(x+4)=0 ?

The solutions to the equation (x-2)*(x+4)=0 are x=2,x=-4

Find the zeros of (x-2)*(x+4)=0

The zeros of (x-2)*(x+4)=0 are x=2,x=-4

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(x - 2) \cdot (x + 4) = 0

x = 2, x = - 4

Solution steps

(x - 2) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

(5 x + 8) (7 x - 5) = 0

a = 34 x^{2} + x

r^{2} = (\frac{a}{2})^{2} + (\frac{a}{2})^{2}

- 14 = 5 n - n^{2}

2 x^{2} + 3 x + c = 0

What are the solutions to the equation (x-2)*(x+4)=0 ?
The solutions to the equation (x-2)*(x+4)=0 are x=2,x=-4
Find the zeros of (x-2)*(x+4)=0
The zeros of (x-2)*(x+4)=0 are x=2,x=-4