What is the answer to (4^{x^2})(2^{-6x})= 1/16 ?

The answer to (4^{x^2})(2^{-6x})= 1/16 is x=2,x=1

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(4^{x^2})(2^{-6x})= 1/16

(4^{x^{2}}) (2^{- 6 x}) = \frac{1}{16}

x = 2, x = 1

Solution steps

(4^{x^{2}}) (2^{- 6 x}) = \frac{1}{16}

Apply exponent rules

2 x^{2} - 6 x = - 4

Solve

2 x^{2} - 6 x = - 4 : x = 2, x = 1

x = 2, x = 1

2^{x} = 16

3^{2 x} = 6^{x - 2}

(- 10)^{x} = 1000

3^{x} = 0

∣ 2^{x} - 1 ∣ + ∣ 2^{x} + 1 ∣ = 2

What is the answer to (4^{x^2})(2^{-6x})= 1/16 ?
The answer to (4^{x^2})(2^{-6x})= 1/16 is x=2,x=1
Solve for x: (4^{x^2})(2^{-6x})= 1/16
The solution is x=2,x=1