What is the answer to 2^{x+4}-2^{x+2}=1 ?

The answer to 2^{x+4}-2^{x+2}=1 is x=-(ln(3))/(ln(2))-2

Solve for x: 2^{x+4}-2^{x+2}=1

The solution is x=-(ln(3))/(ln(2))-2

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2^{x + 4} - 2^{x + 2} = 1

x = - \frac{ln ( 3 )}{ln ( 2 )} - 2

Decimal Notation

x = - 3.58496 \dots

Solution steps

2^{x + 4} - 2^{x + 2} = 1

Factor

2^{x + 4} - 2^{x + 2} : 3 \cdot 2^{x + 2}

3 \cdot 2^{x + 2} = 1

Divide both sides by

3

2^{x + 2} = \frac{1}{3}

Apply exponent rules

(x + 2) ln (2) = ln (\frac{1}{3})

Solve

(x + 2) ln (2) = ln (\frac{1}{3}) : x = - \frac{ln ( 3 )}{ln ( 2 )} - 2

x = - \frac{ln ( 3 )}{ln ( 2 )} - 2

4^{x} + 1 0^{x} = 2 5^{x}

\frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} = 3

(2^{x})^{6} = (2^{9})^{2}

4^{x - 1} \cdot (0.5)^{3 - 2 x} = (\frac{1}{8})^{x}

3^{1 - x} = \frac{1}{( 3 )}

What is the answer to 2^{x+4}-2^{x+2}=1 ?
The answer to 2^{x+4}-2^{x+2}=1 is x=-(ln(3))/(ln(2))-2
Solve for x: 2^{x+4}-2^{x+2}=1
The solution is x=-(ln(3))/(ln(2))-2