What is the answer to solvefor y,e^y-p^3-p=0 ?

The answer to solvefor y,e^y-p^3-p=0 is y=ln(p^3+p)

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solvefor y,e^y-p^3-p=0

solve for

y, e^{y} - p^{3} - p = 0

y = ln (p^{3} + p)

Solution steps

e^{y} - p^{3} - p = 0

Move

p^{3}

to the right side

e^{y} - p = p^{3}

Move

p

to the right side

e^{y} = p^{3} + p

Apply exponent rules

y = ln (p^{3} + p)

729 \cdot (2^{n - 5})^{n} - 64 \cdot (3^{n})^{n - 5} = 0

4^{\frac{1}{( l o g _{2} ( x ) )}} = 2

8^{x} = 1 6^{- 1} \cdot 3 2^{x}

\frac{1}{64} = (\frac{1}{2})^{n - 1}

3^{2 x + 1} = 5^{2 x + 1}

What is the answer to solvefor y,e^y-p^3-p=0 ?
The answer to solvefor y,e^y-p^3-p=0 is y=ln(p^3+p)