What is the answer to 2^{x+2}+2^{x-1}=9 ?

The answer to 2^{x+2}+2^{x-1}=9 is x=1

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2^{x+2}+2^{x-1}=9

2^{x + 2} + 2^{x - 1} = 9

x = 1

Solution steps

2^{x + 2} + 2^{x - 1} = 9

Factor

2^{x + 2} + 2^{x - 1} : 9 \cdot 2^{x - 1}

9 \cdot 2^{x - 1} = 9

Divide both sides by

9

2^{x - 1} = 1

Apply exponent rules

(x - 1) ln (2) = ln (1)

Solve

(x - 1) ln (2) = ln (1) : x = 1

x = 1

lo g_{10} (9^{x}) = 1.5

1 0^{x} = 33

3^{x} + 2 x - 5 = 0

2^{5 x + 2} = 8^{9}

(\frac{( 2 ^{1 - 2 x} )}{( 2 ^{x + 3} )})^{3} = 4

What is the answer to 2^{x+2}+2^{x-1}=9 ?
The answer to 2^{x+2}+2^{x-1}=9 is x=1
Solve for x: 2^{x+2}+2^{x-1}=9
The solution is x=1