What is the answer to (3^{3x-2})/((3^{x+3))}=81 ?

The answer to (3^{3x-2})/((3^{x+3))}=81 is x= 9/2

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(3^{3x-2})/((3^{x+3))}=81

\frac{3 ^{3 x - 2}}{( 3 ^{x + 3} )} = 81

x = \frac{9}{2}

Decimal Notation

x = 4.5

Solution steps

\frac{3 ^{3 x - 2}}{( 3 ^{x + 3} )} = 81

Apply exponent rules

2 x - 5 = 4

Solve

2 x - 5 = 4 : x = \frac{9}{2}

x = \frac{9}{2}

Verify Solutions:

x = \frac{9}{2}

True

The solution is

x = \frac{9}{2}

4^{x + 1} + 4^{1 - x} = 10

21 \cdot 3^{x} - 2^{x + 3} = 3^{x + 1}

5^{2 x - 1} = 2 5^{x - 1}

(2. 1^{- 8})^{3} = 80. 1^{a}

9^{3 x} = (\frac{1}{3})^{2 x - 1}

What is the answer to (3^{3x-2})/((3^{x+3))}=81 ?
The answer to (3^{3x-2})/((3^{x+3))}=81 is x= 9/2
Solve for x: (3^{3x-2})/((3^{x+3))}=81
The solution is x= 9/2