What is the answer to 21*3^x-2^{x+3}=3^{x+1} ?

The answer to 21*3^x-2^{x+3}=3^{x+1} is x=(2ln(2)-2ln(3))/(ln(3)-ln(2))

Solve for x: 21*3^x-2^{x+3}=3^{x+1}

The solution is x=(2ln(2)-2ln(3))/(ln(3)-ln(2))

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21 \cdot 3^{x} - 2^{x + 3} = 3^{x + 1}

x = \frac{2 ln ( 2 ) - 2 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = - 2

Solution steps

21 \cdot 3^{x} - 2^{x + 3} = 3^{x + 1}

Move

3^{x + 1}

to the left side

2 \cdot 3^{2 + x} - 2^{x + 3} = 0

Move

2^{x + 3}

to the right side

2 \cdot 3^{2 + x} = 2^{x + 3}

Apply exponent rules

ln (2) + (2 + x) ln (3) = (x + 3) ln (2)

Solve

ln (2) + (2 + x) ln (3) = (x + 3) ln (2) : x = \frac{2 ln ( 2 ) - 2 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{2 ln ( 2 ) - 2 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

5^{2 x - 1} = 2 5^{x - 1}

(2. 1^{- 8})^{3} = 80. 1^{a}

9^{3 x} = (\frac{1}{3})^{2 x - 1}

2^{x} = \frac{2}{3}

8^{9 x + 1} = 2^{x^{2} + 29 x}

What is the answer to 21*3^x-2^{x+3}=3^{x+1} ?
The answer to 21*3^x-2^{x+3}=3^{x+1} is x=(2ln(2)-2ln(3))/(ln(3)-ln(2))
Solve for x: 21*3^x-2^{x+3}=3^{x+1}
The solution is x=(2ln(2)-2ln(3))/(ln(3)-ln(2))