What is the answer to 11^{-3x}=17^{x-6} ?

The answer to 11^{-3x}=17^{x-6} is x=(6ln(17))/(3ln(11)+ln(17))

Solve for x: 11^{-3x}=17^{x-6}

The solution is x=(6ln(17))/(3ln(11)+ln(17))

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1 1^{- 3 x} = 1 7^{x - 6}

x = \frac{6 ln ( 17 )}{3 ln ( 11 ) + ln ( 17 )}

Decimal Notation

x = 1.69536 \dots

Solution steps

1 1^{- 3 x} = 1 7^{x - 6}

Apply exponent rules

- 3 x ln (11) = (x - 6) ln (17)

Solve

- 3 x ln (11) = (x - 6) ln (17) : x = \frac{6 ln ( 17 )}{3 ln ( 11 ) + ln ( 17 )}

x = \frac{6 ln ( 17 )}{3 ln ( 11 ) + ln ( 17 )}

2 (6^{x}) - 54 (2^{x}) - 16 (3^{x}) + 432 = 0

7^{x + 2} + 7^{x + 1} = 8

12000 = 200 e^{0.01 t}

4^{x} = 81

2^{x - 2} = 4^{2021}

What is the answer to 11^{-3x}=17^{x-6} ?
The answer to 11^{-3x}=17^{x-6} is x=(6ln(17))/(3ln(11)+ln(17))
Solve for x: 11^{-3x}=17^{x-6}
The solution is x=(6ln(17))/(3ln(11)+ln(17))