What is the answer to 7^{x+2}+7^{x+1}=8 ?

The answer to 7^{x+2}+7^{x+1}=8 is x=-1

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7^{x+2}+7^{x+1}=8

7^{x + 2} + 7^{x + 1} = 8

x = - 1

Solution steps

7^{x + 2} + 7^{x + 1} = 8

Factor

7^{x + 2} + 7^{x + 1} : 8 \cdot 7^{x + 1}

8 \cdot 7^{x + 1} = 8

Divide both sides by

8

7^{x + 1} = 1

Apply exponent rules

(x + 1) ln (7) = ln (1)

Solve

(x + 1) ln (7) = ln (1) : x = - 1

x = - 1

12000 = 200 e^{0.01 t}

4^{x} = 81

2^{x - 2} = 4^{2021}

3^{x} + 3^{x + 1} = 36

3^{x} - 0.5 = 0

What is the answer to 7^{x+2}+7^{x+1}=8 ?
The answer to 7^{x+2}+7^{x+1}=8 is x=-1
Solve for x: 7^{x+2}+7^{x+1}=8
The solution is x=-1