What are the solutions to the equation 4x^2-16x+8=0 ?

The solutions to the equation 4x^2-16x+8=0 are x=2+sqrt(2),x=2-sqrt(2)

Find the zeros of 4x^2-16x+8=0

The zeros of 4x^2-16x+8=0 are x=2+sqrt(2),x=2-sqrt(2)

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4 x^{2} - 16 x + 8 = 0

x = 2 + 2, x = 2 - 2

Solution steps

4 x^{2} - 16 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 8}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 8 = 82

x_{1, 2} = \frac{- ( - 16 ) \pm 8 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 8 2}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 8 2}{2 \cdot 4}

x = \frac{- ( - 16 ) + 8 2}{2 \cdot 4} : 2 + 2

x = \frac{- ( - 16 ) - 8 2}{2 \cdot 4} : 2 - 2

The solutions to the quadratic equation are:

x = 2 + 2, x = 2 - 2

\frac{2 ^{\frac{3}{2}}}{3}

3 x^{2} - 12 x = 10

\frac{4 x}{5} - \frac{2 x}{15} = \frac{x - 1}{2}

\frac{8 x ^{6} y}{8 x ^{3} y ^{7}}

3 x^{2} - 42 x - 5 = 0

What are the solutions to the equation 4x^2-16x+8=0 ?
The solutions to the equation 4x^2-16x+8=0 are x=2+sqrt(2),x=2-sqrt(2)
Find the zeros of 4x^2-16x+8=0
The zeros of 4x^2-16x+8=0 are x=2+sqrt(2),x=2-sqrt(2)