What is the answer to 3^{2x}+5=3^{x+1} ?

The answer to 3^{2x}+5=3^{x+1} is No Solution for x\in\mathbb{R}

Solve for x: 3^{2x}+5=3^{x+1}

The solution is No Solution for x\in\mathbb{R}

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3^{2 x} + 5 = 3^{x + 1}

No Solution for x \in R

Solution steps

3^{2 x} + 5 = 3^{x + 1}

Apply exponent rules

(3^{x})^{2} + 5 = 3^{x} \cdot 3^{1}

Rewrite the equation with

3^{x} = u

(u)^{2} + 5 = u \cdot 3^{1}

Solve

u^{2} + 5 = u \cdot 3^{1} :

No Solution for

u \in R

No Solution for x \in R

5^{- x} = 2

2^{x - 3} = 6^{2 x - 1}

1 6^{2 x + 10} = 1 6^{2 x - 1}

9^{2 - x} = 3

1 = 2^{n}

What is the answer to 3^{2x}+5=3^{x+1} ?
The answer to 3^{2x}+5=3^{x+1} is No Solution for x\in\mathbb{R}
Solve for x: 3^{2x}+5=3^{x+1}
The solution is No Solution for x\in\mathbb{R}