What is the answer to ((32^{x-4}))/((4^{x-4))}=8^{3x+2} ?

The answer to ((32^{x-4}))/((4^{x-4))}=8^{3x+2} is x=-3

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((32^{x-4}))/((4^{x-4))}=8^{3x+2}

\frac{( 3 2 ^{x - 4} )}{( 4 ^{x - 4} )} = 8^{3 x + 2}

x = - 3

Solution steps

\frac{( 3 2 ^{x - 4} )}{( 4 ^{x - 4} )} = 8^{3 x + 2}

Apply exponent rules

5 (x - 4) + 2 (- x + 4) = 3 (3 x + 2)

Solve

5 (x - 4) + 2 (- x + 4) = 3 (3 x + 2) : x = - 3

x = - 3

Verify Solutions:

x = - 3

True

The solution is

x = - 3

3. 2^{x} + 2^{- 6} = 48

m, 2^{m} 0. 3^{n} 0.72 = 1

x, \frac{1}{a ^{x}} = e^{- y}

6 4^{2 x - 5} = 3 2^{x - 4}

n, 2 = t + t^{n}

What is the answer to ((32^{x-4}))/((4^{x-4))}=8^{3x+2} ?
The answer to ((32^{x-4}))/((4^{x-4))}=8^{3x+2} is x=-3
Solve for x: ((32^{x-4}))/((4^{x-4))}=8^{3x+2}
The solution is x=-3