What is the answer to 3.2^x+2^{-6}=48 ?

The answer to 3.2^x+2^{-6}=48 is x=(ln(3071/64))/(ln(3.2))

Solve for x: 3.2^x+2^{-6}=48

The solution is x=(ln(3071/64))/(ln(3.2))

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3. 2^{x} + 2^{- 6} = 48

x = \frac{ln ( \frac{3071}{64} )}{ln ( 3.2 )}

Decimal Notation

x = 3.32792 \dots

Solution steps

3. 2^{x} + 2^{- 6} = 48

Move

2^{- 6}

to the right side

3. 2^{x} = 48 - 2^{- 6}

Simplify

48 - 2^{- 6} : 48 - \frac{1}{64}

3. 2^{x} = 48 - \frac{1}{64}

Apply exponent rules

x ln (3.2) = ln (48 - \frac{1}{64})

Solve

x ln (3.2) = ln (48 - \frac{1}{64}) : x = \frac{ln ( \frac{3071}{64} )}{ln ( 3.2 )}

x = \frac{ln ( \frac{3071}{64} )}{ln ( 3.2 )}

m, 2^{m} 0. 3^{n} 0.72 = 1

x, \frac{1}{a ^{x}} = e^{- y}

6 4^{2 x - 5} = 3 2^{x - 4}

n, 2 = t + t^{n}

\frac{( 2 ^{x} \cdot 3 ^{x} )}{( 1 2 ^{x} )} = \frac{1}{8}

What is the answer to 3.2^x+2^{-6}=48 ?
The answer to 3.2^x+2^{-6}=48 is x=(ln(3071/64))/(ln(3.2))
Solve for x: 3.2^x+2^{-6}=48
The solution is x=(ln(3071/64))/(ln(3.2))