What is the answer to 3^{x+1}+3^{4-x}=36 ?

The answer to 3^{x+1}+3^{4-x}=36 is x=2,x=1

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3^{x+1}+3^{4-x}=36

3^{x + 1} + 3^{4 - x} = 36

x = 2, x = 1

Solution steps

3^{x + 1} + 3^{4 - x} = 36

Apply exponent rules

3^{x} \cdot 3^{1} + (3^{x})^{- 1} \cdot 3^{4} = 36

Rewrite the equation with

3^{x} = u

u \cdot 3^{1} + (u)^{- 1} \cdot 3^{4} = 36

Solve

u \cdot 3^{1} + u^{- 1} \cdot 3^{4} = 36 : u = 9, u = 3

u = 9, u = 3

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 9 : x = 2

Solve

3^{x} = 3 : x = 1

x = 2, x = 1

0 = e^{x}

x, d^{2} + d - 2 = e^{x}

3^{40} + 3^{40} + 3^{x} = 3^{41}

5^{x + 1} = 5^{x} + 100

9 e^{\frac{- x}{2}} + 12 e^{\frac{- x}{6}} = 0

What is the answer to 3^{x+1}+3^{4-x}=36 ?
The answer to 3^{x+1}+3^{4-x}=36 is x=2,x=1
Solve for x: 3^{x+1}+3^{4-x}=36
The solution is x=2,x=1