What is the answer to 16^x+20^x+25^x=0 ?

The answer to 16^x+20^x+25^x=0 is No Solution for x\in\mathbb{R}

Solve for x: 16^x+20^x+25^x=0

The solution is No Solution for x\in\mathbb{R}

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Popular >

1 6^{x} + 2 0^{x} + 2 5^{x} = 0

No Solution for x \in R

Solution steps

1 6^{x} + 2 0^{x} + 2 5^{x} = 0

Divide both sides by

1 6^{x}

\frac{1 6 ^{x}}{1 6 ^{x}} + \frac{2 0 ^{x}}{1 6 ^{x}} + \frac{2 5 ^{x}}{1 6 ^{x}} = \frac{0}{1 6 ^{x}}

Simplify

1 + (\frac{5}{4})^{x} + (\frac{25}{16})^{x} = 0

Apply exponent rules

1 + (\frac{5}{4})^{x} + ((\frac{5}{4})^{x})^{2} = 0

Rewrite the equation with

(\frac{5}{4})^{x} = u

1 + u + (u)^{2} = 0

Solve

1 + u + u^{2} = 0 :

No Solution for

u \in R

No Solution for x \in R

3 2^{x} = 8

(\frac{1}{9})^{6 x + 1} = 9^{7 - x}

x, y^{x} - y^{y} = - 26

x^{(l o g_{10} (x)) + 2} = 1 0^{(l o g_{10} (x)) + 2}

(- 3)^{x} = 87

What is the answer to 16^x+20^x+25^x=0 ?
The answer to 16^x+20^x+25^x=0 is No Solution for x\in\mathbb{R}
Solve for x: 16^x+20^x+25^x=0
The solution is No Solution for x\in\mathbb{R}