What is the answer to solvefor x,q(3^{2x+1})=54 ?

The answer to solvefor x,q(3^{2x+1})=54 is x=(ln((18)/q))/(2ln(3))

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solvefor x,q(3^{2x+1})=54

solve for

x, q (3^{2 x + 1}) = 54

x = \frac{ln ( \frac{18}{q} )}{2 ln ( 3 )}

Solution steps

q (3^{2 x + 1}) = 54

Divide both sides by

q

3^{2 x + 1} = \frac{54}{q}

Apply exponent rules

(2 x + 1) ln (3) = ln (\frac{54}{q})

Solve

(2 x + 1) ln (3) = ln (\frac{54}{q}) : x = \frac{ln ( \frac{18}{q} )}{2 ln ( 3 )}

x = \frac{ln ( \frac{18}{q} )}{2 ln ( 3 )}

3 \cdot 2^{x + 2} - 5 \cdot 2^{x + 1} - 2^{x} = 2

4^{t} + 6^{t} = 9^{t}

5^{y} = 3^{y + 1}

3^{3 - x} = x

8 1^{x + 1} + 3^{4 x} = 243

What is the answer to solvefor x,q(3^{2x+1})=54 ?
The answer to solvefor x,q(3^{2x+1})=54 is x=(ln((18)/q))/(2ln(3))