What is the answer to 5^y=3^{y+1} ?

The answer to 5^y=3^{y+1} is y=(ln(3))/(ln(5)-ln(3))

Solve for y: 5^y=3^{y+1}

The solution is y=(ln(3))/(ln(5)-ln(3))

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5^{y} = 3^{y + 1}

y = \frac{ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

Decimal Notation

y = 2.15066 \dots

Solution steps

5^{y} = 3^{y + 1}

Apply exponent rules

y ln (5) = (y + 1) ln (3)

Solve

y ln (5) = (y + 1) ln (3) : y = \frac{ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

y = \frac{ln ( 3 )}{ln ( 5 ) - ln ( 3 )}

3^{3 - x} = x

8 1^{x + 1} + 3^{4 x} = 243

1 3^{9} x = 1 1^{x + 5}

9^{\frac{x - 1}{2}} = (3^{x})^{2}

2^{2 x - 3} = 4^{x^{2} - 3 x - 1}

What is the answer to 5^y=3^{y+1} ?
The answer to 5^y=3^{y+1} is y=(ln(3))/(ln(5)-ln(3))
Solve for y: 5^y=3^{y+1}
The solution is y=(ln(3))/(ln(5)-ln(3))