What is the answer to 81^{x+1}+3^{4x}=243 ?

The answer to 81^{x+1}+3^{4x}=243 is x=(ln(243/82))/(4ln(3))

Solve for x: 81^{x+1}+3^{4x}=243

The solution is x=(ln(243/82))/(4ln(3))

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8 1^{x + 1} + 3^{4 x} = 243

x = \frac{ln ( \frac{243}{82} )}{4 ln ( 3 )}

Decimal Notation

x = 0.24720 \dots

Solution steps

8 1^{x + 1} + 3^{4 x} = 243

Apply exponent rules

4 x ln (3) = ln (\frac{243}{82})

Solve

4 x ln (3) = ln (\frac{243}{82}) : x = \frac{ln ( \frac{243}{82} )}{4 ln ( 3 )}

x = \frac{ln ( \frac{243}{82} )}{4 ln ( 3 )}

1 3^{9} x = 1 1^{x + 5}

9^{\frac{x - 1}{2}} = (3^{x})^{2}

2^{2 x - 3} = 4^{x^{2} - 3 x - 1}

2^{2 x + 1} - 15 (2^{x}) - 8 = 0

x, (2007)^{x} + (2007)^{y} = 1

What is the answer to 81^{x+1}+3^{4x}=243 ?
The answer to 81^{x+1}+3^{4x}=243 is x=(ln(243/82))/(4ln(3))
Solve for x: 81^{x+1}+3^{4x}=243
The solution is x=(ln(243/82))/(4ln(3))