What is the answer to 9^{(x-1)/2}=(3^x)^2 ?

The answer to 9^{(x-1)/2}=(3^x)^2 is x=-1

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9^{(x-1)/2}=(3^x)^2

9^{\frac{x - 1}{2}} = (3^{x})^{2}

x = - 1

Solution steps

9^{\frac{x - 1}{2}} = (3^{x})^{2}

Apply exponent rules

x - 1 = x \cdot 2

Solve

x - 1 = x \cdot 2 : x = - 1

x = - 1

2^{2 x - 3} = 4^{x^{2} - 3 x - 1}

2^{2 x + 1} - 15 (2^{x}) - 8 = 0

x, (2007)^{x} + (2007)^{y} = 1

n = \frac{( 2 ^{n + 4} - 2 ^{n + 3} )}{( 2 ^{n + 4} )}

\frac{8 1 ^{2}}{( 72 9 ^{1} ) ^{- x}} = (9^{2})^{x}

What is the answer to 9^{(x-1)/2}=(3^x)^2 ?
The answer to 9^{(x-1)/2}=(3^x)^2 is x=-1
Solve for x: 9^{(x-1)/2}=(3^x)^2
The solution is x=-1