What is the answer to solvefor p,2^p-2^q=48 ?

The answer to solvefor p,2^p-2^q=48 is p=(ln(48+2^q))/(ln(2))

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solvefor p,2^p-2^q=48

solve for

p, 2^{p} - 2^{q} = 48

p = \frac{ln ( 48 + 2 ^{q} )}{ln ( 2 )}

Solution steps

2^{p} - 2^{q} = 48

Move

2^{q}

to the right side

2^{p} = 48 + 2^{q}

Apply exponent rules

p ln (2) = ln (48 + 2^{q})

Solve

p ln (2) = ln (48 + 2^{q}) : p = \frac{ln ( 48 + 2 ^{q} )}{ln ( 2 )}

p = \frac{ln ( 48 + 2 ^{q} )}{ln ( 2 )}

3^{x} \cdot 9^{2 x + 1} = 81

m, 3^{m} - 2^{n} = 2

3^{x + 2} + 3^{- x} = 10

1.2 1^{x} = 100

4^{- 6} x = 1 7^{x} + 4

What is the answer to solvefor p,2^p-2^q=48 ?
The answer to solvefor p,2^p-2^q=48 is p=(ln(48+2^q))/(ln(2))