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Popular >

((2^{x-1}*4^{2x+1}))/((8^{x-1))}=64

Solution

\frac{( 2 ^{x - 1} \cdot 4 ^{2 x + 1} )}{( 8 ^{x - 1} )} = 64

Solution

x = 1

Solution steps

\frac{( 2 ^{x - 1} \cdot 4 ^{2 x + 1} )}{( 8 ^{x - 1} )} = 64

Simplify

\frac{2 ^{x - 1} \cdot 4 ^{2 x + 1}}{8 ^{x - 1}} : \frac{2 ^{5 x + 1}}{8 ^{x - 1}}

\frac{2 ^{5 x + 1}}{8 ^{x - 1}} = 64

Multiply both sides by

8^{x - 1}

2^{5 x + 1} = 2^{6 + 3 (x - 1)}

Solve

2^{5 x + 1} = 2^{6 + 3 (x - 1)} : x = 1

x = 1

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Frequently Asked Questions (FAQ)

What is the answer to ((2^{x-1}*4^{2x+1}))/((8^{x-1))}=64 ?
The answer to ((2^{x-1}*4^{2x+1}))/((8^{x-1))}=64 is x=1
Solve for x: ((2^{x-1}*4^{2x+1}))/((8^{x-1))}=64
The solution is x=1