What are the solutions to the equation 8x^2-24=3x^2-9 ?

The solutions to the equation 8x^2-24=3x^2-9 are x=sqrt(3),x=-sqrt(3)

Find the zeros of 8x^2-24=3x^2-9

The zeros of 8x^2-24=3x^2-9 are x=sqrt(3),x=-sqrt(3)

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8 x^{2} - 24 = 3 x^{2} - 9

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

8 x^{2} - 24 = 3 x^{2} - 9

Move

24

to the right side

8 x^{2} = 3 x^{2} + 15

Move

3 x^{2}

to the left side

5 x^{2} = 15

Divide both sides by

5

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

12 b^{2} - 43 b + 36

\frac{\frac{1}{2}}{\frac{3}{4}}

- 6 x^{2} - 2 - 3 x = - 8

- 2 x^{2} + 8 x + 7 = 0

- 1 \leq y \leq 3

What are the solutions to the equation 8x^2-24=3x^2-9 ?
The solutions to the equation 8x^2-24=3x^2-9 are x=sqrt(3),x=-sqrt(3)
Find the zeros of 8x^2-24=3x^2-9
The zeros of 8x^2-24=3x^2-9 are x=sqrt(3),x=-sqrt(3)