What are the solutions to the equation -96z^2=-48 ?

The solutions to the equation -96z^2=-48 are z= 1/(sqrt(2)),z=-1/(sqrt(2))

Find the zeros of -96z^2=-48

The zeros of -96z^2=-48 are z= 1/(sqrt(2)),z=-1/(sqrt(2))

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- 96 z^{2} = - 48

z = \frac{1}{2}, z = - \frac{1}{2}

Solution steps

- 96 z^{2} = - 48

Divide both sides by

- 96

z^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = \frac{1}{2}, z = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

z = \frac{1}{2}, z = - \frac{1}{2}

x^{2} + 6 x = 2

3 x^{2} + 10 x + 6 = 0

4 a^{2} - a - 5

(5 x + 2) (x + 1) = 1

3 (3)

What are the solutions to the equation -96z^2=-48 ?
The solutions to the equation -96z^2=-48 are z= 1/(sqrt(2)),z=-1/(sqrt(2))
Find the zeros of -96z^2=-48
The zeros of -96z^2=-48 are z= 1/(sqrt(2)),z=-1/(sqrt(2))