What is the answer to solvefor x,y=((2y+x))/x ?

The answer to solvefor x,y=((2y+x))/x is x=(2y)/(y-1);\quad y\ne 1

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solvefor x,y=((2y+x))/x

solve for

x, y = \frac{( 2 y + x )}{x}

x = \frac{2 y}{y - 1}; y \neq = 1

Solution steps

y = \frac{( 2 y + x )}{x}

Simplify

\frac{( 2 y + x )}{x} : \frac{2 y + x}{x}

y = \frac{2 y + x}{x}

Multiply both sides by

x

y x = 2 y + x

Move

x

to the left side

y x - x = 2 y

Factor

y x - x : x (y - 1)

x (y - 1) = 2 y

Divide both sides by

y - 1; y \neq = 1

x = \frac{2 y}{y - 1}; y \neq = 1

8 = \frac{( 250 k )}{( t _{1} - 250 k )}

0.0507 = \frac{( \frac{2.64}{m} )}{( \frac{2.64}{m} + \frac{32}{74} )}

\frac{x + 1}{x - 3} = \frac{0 x ^{3} + 1}{x ^{3}}

\frac{x ^{2} + 1}{x - 5 ( x + \frac{1}{x} ) + 8} = 0

\frac{y ^{2} - 5}{3 y} = - 13

What is the answer to solvefor x,y=((2y+x))/x ?
The answer to solvefor x,y=((2y+x))/x is x=(2y)/(y-1);\quad y\ne 1