What is the answer to solvefor x, 1/x = 4/((y-x)^2) ?

The answer to solvefor x, 1/x = 4/((y-x)^2) is x=y+2+2sqrt(y+1),x=y+2-2sqrt(y+1)

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solvefor x, 1/x = 4/((y-x)^2)

solve for

x, \frac{1}{x} = \frac{4}{( y - x ) ^{2}}

x = y + 2 + 2 y + 1, x = y + 2 - 2 y + 1

Solution steps

\frac{1}{x} = \frac{4}{( y - x ) ^{2}}

Cross multiply

(y - x)^{2} = x \cdot 4

Solve

(y - x)^{2} = x \cdot 4 : x = y + 2 + 2 y + 1, x = y + 2 - 2 y + 1

x = y + 2 + 2 y + 1, x = y + 2 - 2 y + 1

\frac{6 q ^{2} + 1}{2} = \frac{7}{2 q}

\frac{\frac{16}{7}}{\frac{4}{9}} = \frac{\frac{9}{14}}{t}

(\frac{x}{( x + 5 )}) - (\frac{11 x}{( 11 x - 8 )}) + (\frac{7}{( 6 - 4 x )}) = 0

x^{- 4} - 6 x^{- 2} + 8 = 0

\frac{( x ) ^{2}}{( ( \frac{4}{5} ) ^{- 4} )} = (\frac{1}{x})^{2}

What is the answer to solvefor x, 1/x = 4/((y-x)^2) ?
The answer to solvefor x, 1/x = 4/((y-x)^2) is x=y+2+2sqrt(y+1),x=y+2-2sqrt(y+1)