What is the answer to (x/((x+5)))-((11x)/((11x-8)))+(7/((6-4x)))=0 ?

The answer to (x/((x+5)))-((11x)/((11x-8)))+(7/((6-4x)))=0 is x=-40/47 ,x=1

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(x/((x+5)))-((11x)/((11x-8)))+(7/((6-4x)))=0

(\frac{x}{( x + 5 )}) - (\frac{11 x}{( 11 x - 8 )}) + (\frac{7}{( 6 - 4 x )}) = 0

x = - \frac{40}{47}, x = 1

Decimal Notation

x = - 0.85106 \dots, x = 1

Solution steps

(\frac{x}{( x + 5 )}) - (\frac{11 x}{( 11 x - 8 )}) + (\frac{7}{( 6 - 4 x )}) = 0

Multiply by LCM

2 x (2 x - 3) (11 x - 8) - 22 x (x + 5) (2 x - 3) - 7 (x + 5) (11 x - 8) = 0

Solve

2 x (2 x - 3) (11 x - 8) - 22 x (x + 5) (2 x - 3) - 7 (x + 5) (11 x - 8) = 0 : x = - \frac{40}{47}, x = 1

x = - \frac{40}{47}, x = 1

Verify Solutions

Find undefined (singularity) points:

x = - 5, x = \frac{8}{11}, x = \frac{3}{2}

Combine undefined points with solutions:

x = - \frac{40}{47}, x = 1

x^{- 4} - 6 x^{- 2} + 8 = 0

\frac{( x ) ^{2}}{( ( \frac{4}{5} ) ^{- 4} )} = (\frac{1}{x})^{2}

\frac{1}{( x + 1 )} + \frac{3}{( x + 4 )} = \frac{4}{( x + 3 )}

x, \frac{1}{( 2 x )} + \frac{1}{( 3 y )} = 2

\frac{\frac{9}{5}}{x} = \frac{( \frac{3}{2} + \frac{1}{4} )}{( 1 + \frac{7}{9} )}

What is the answer to (x/((x+5)))-((11x)/((11x-8)))+(7/((6-4x)))=0 ?
The answer to (x/((x+5)))-((11x)/((11x-8)))+(7/((6-4x)))=0 is x=-40/47 ,x=1
Solve for x: (x/((x+5)))-((11x)/((11x-8)))+(7/((6-4x)))=0
The solution is x=-40/47 ,x=1