What is the answer to 1/(x^2)=x^{-2} ?

The answer to 1/(x^2)=x^{-2} is x\ne 0

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1/(x^2)=x^{-2}

\frac{1}{x ^{2}} = x^{- 2}

x \neq = 0

Solution steps

\frac{1}{x ^{2}} = x^{- 2}

Refine

\frac{1}{x ^{2}} = \frac{1}{x ^{2}}

Subtract

\frac{1}{x ^{2}}

from both sides

\frac{1}{x ^{2}} - \frac{1}{x ^{2}} = \frac{1}{x ^{2}} - \frac{1}{x ^{2}}

Simplify

0 = 0

Both sides are equal

True for all x

Verify Solutions

Find undefined (singularity) points:

x = 0

Since the equation is undefined for:

0

x \neq = 0

2 (\frac{x ^{2} + 1}{x ^{2}}) - 3 (\frac{x - 1}{x}) - 4 = 0

x, (\frac{1}{x}) - (\frac{1}{y}) - 2 = 0

y, 3 x^{2} y^{4} = 5 x^{3} y^{- 3} z^{2}

\frac{( 1 + x ^{4} + x ^{8} )}{x ^{4}} = 4

\frac{2 ( x + 1 )}{3 + 4 ( x - 2 )} = \frac{x}{2 + 5}