What is the answer to y= 1/((4-y^2)) ?

The answer to y= 1/((4-y^2)) is y\approx 0.25410…,y\approx 1.86080…,y\approx-2.11490…

Solve for y: y= 1/((4-y^2))

The solution is y\approx 0.25410…,y\approx 1.86080…,y\approx-2.11490…

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y = \frac{1}{( 4 - y ^{2} )}

y \approx 0.25410 \dots, y \approx 1.86080 \dots, y \approx - 2.11490 \dots

Solution steps

y = \frac{1}{( 4 - y ^{2} )}

Simplify

\frac{1}{( 4 - y ^{2} )} : \frac{1}{4 - y ^{2}}

y = \frac{1}{4 - y ^{2}}

Multiply both sides by

4 - y^{2}

y (4 - y^{2}) = 1

Solve

y (4 - y^{2}) = 1 : y \approx 0.25410 \dots, y \approx 1.86080 \dots, y \approx - 2.11490 \dots

y \approx 0.25410 \dots, y \approx 1.86080 \dots, y \approx - 2.11490 \dots

Verify Solutions

Find undefined (singularity) points:

y = 2, y = - 2

Combine undefined points with solutions:

y \approx 0.25410 \dots, y \approx 1.86080 \dots, y \approx - 2.11490 \dots

b, \frac{1}{d ^{2}} = \frac{1}{b ^{2}} + \frac{1}{c ^{2}}

a, a - c = 2 \frac{( a + b )}{a}

e^{l} n x = \frac{x ^{1}}{x}

(\frac{3}{4 x + 1})^{3} - (x + 2)^{3} + (0.25 x + 1)^{3} = 0

\frac{3}{4 x ^{2} - x - 1} = 0

What is the answer to y= 1/((4-y^2)) ?
The answer to y= 1/((4-y^2)) is y\approx 0.25410…,y\approx 1.86080…,y\approx-2.11490…
Solve for y: y= 1/((4-y^2))
The solution is y\approx 0.25410…,y\approx 1.86080…,y\approx-2.11490…