What is the answer to sqrt(4-3x)-2sqrt(36-27x)+5=0 ?

The answer to sqrt(4-3x)-2sqrt(36-27x)+5=0 is x=1

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sqrt(4-3x)-2sqrt(36-27x)+5=0

4 - 3 x - 2 36 - 27 x + 5 = 0

x = 1

Solution steps

4 - 3 x - 2 36 - 27 x + 5 = 0

Factor

4 - 3 x - 2 36 - 27 x + 5 : - 5 (4 - 3 x - 1)

- 5 (4 - 3 x - 1) = 0

Divide both sides by

- 5

4 - 3 x - 1 = 0

Move

1

to the right side

4 - 3 x = 1

Square both sides:

4 - 3 x = 1

4 - 3 x = 1

Solve

4 - 3 x = 1 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

\frac{- 1}{5 - \frac{1}{3} \cdot x + 1} = - \frac{17}{10}

x, 20 g \cdot x^{3} - 9^{2} = 2

x - 2 = - 2 x + 14

9 x^{2} - 6 x + 1 = x + 2

5 x^{2} + 8 x + 10 = x^{4} + 4

What is the answer to sqrt(4-3x)-2sqrt(36-27x)+5=0 ?
The answer to sqrt(4-3x)-2sqrt(36-27x)+5=0 is x=1
Solve for x: sqrt(4-3x)-2sqrt(36-27x)+5=0
The solution is x=1