What is the answer to solvefor v,5w=(((v+2)^{1/2}))/3 ?

The answer to solvefor v,5w=(((v+2)^{1/2}))/3 is v=225w^2-2 {w>= 0}

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solvefor v,5w=(((v+2)^{1/2}))/3

solve for

v, 5 w = \frac{( ( v + 2 ) ^{\frac{1}{2}} )}{3}

v = 225 w^{2} - 2 {w \geq 0}

Solution steps

5 w = \frac{( ( v + 2 ) ^{\frac{1}{2}} )}{3}

Multiply both sides by

3

5 w \cdot 3 = \frac{( v + 2 ) ^{\frac{1}{2}}}{3} \cdot 3

Simplify

15 w = (v + 2)^{\frac{1}{2}}

Square both sides:

225 w^{2} = v + 2

225 w^{2} = v + 2

Solve

225 w^{2} = v + 2 : v = 225 w^{2} - 2

v = 225 w^{2} - 2

Verify Solutions:

v = 225 w^{2} - 2 {w \geq 0}

The solution is

v = 225 w^{2} - 2 {w \geq 0}

x, z = x y + y \cdot x^{2} - a^{2} + b

x^{2} + (x - 1)^{2} = 1

(2 x + 5)^{\frac{1}{3}} = 5

(x^{0.16}) + 80 = 122

y - 19 = 2

What is the answer to solvefor v,5w=(((v+2)^{1/2}))/3 ?
The answer to solvefor v,5w=(((v+2)^{1/2}))/3 is v=225w^2-2 {w>= 0}