What is the answer to sqrt(2+\sqrt{3x-5)}=sqrt(x+1) ?

The answer to sqrt(2+\sqrt{3x-5)}=sqrt(x+1) is x=3,x=2

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sqrt(2+\sqrt{3x-5)}=sqrt(x+1)

2 + 3 x - 5 = x + 1

x = 3, x = 2

Solution steps

2 + 3 x - 5 = x + 1

Remove square roots

3 x - 5 = x^{2} - 2 x + 1

Solve

3 x - 5 = x^{2} - 2 x + 1 : x = 3, x = 2

x = 3, x = 2

Verify Solutions:

x = 3

True

, x = 2

True

The solutions are

x = 3, x = 2

y = 8

y^{\frac{7}{3}} = 2187

x^{2} + x + 3 = x - 3

3 7 x^{2} - 6 x - 137 = 0

98 - 2 x^{2} + 3 x + 5 + 2 x^{2} - 7 x - 15 = 0

What is the answer to sqrt(2+\sqrt{3x-5)}=sqrt(x+1) ?
The answer to sqrt(2+\sqrt{3x-5)}=sqrt(x+1) is x=3,x=2
Solve for x: sqrt(2+\sqrt{3x-5)}=sqrt(x+1)
The solution is x=3,x=2