What is the answer to sqrt(x^2+x+3)=x-3 ?

The answer to sqrt(x^2+x+3)=x-3 is No Solution for x\in\mathbb{R}

Solve for x: sqrt(x^2+x+3)=x-3

The solution is No Solution for x\in\mathbb{R}

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x^{2} + x + 3 = x - 3

No Solution for x \in R

Solution steps

x^{2} + x + 3 = x - 3

Square both sides:

x^{2} + x + 3 = x^{2} - 6 x + 9

x^{2} + x + 3 = x^{2} - 6 x + 9

Solve

x^{2} + x + 3 = x^{2} - 6 x + 9 : x = \frac{6}{7}

x = \frac{6}{7}

Verify Solutions:

x = \frac{6}{7}

False

The solution is

No Solution for x \in R

3 7 x^{2} - 6 x - 137 = 0

98 - 2 x^{2} + 3 x + 5 + 2 x^{2} - 7 x - 15 = 0

\frac{6 x ^{2}}{( 2 x + 1 + 1 ) ^{2}} = 2 x + x - 1 + 1

c = \frac{1}{( x ^{2} + x - 2 )}

2 x^{2} + 2 5 x - 5 = 0

What is the answer to sqrt(x^2+x+3)=x-3 ?
The answer to sqrt(x^2+x+3)=x-3 is No Solution for x\in\mathbb{R}
Solve for x: sqrt(x^2+x+3)=x-3
The solution is No Solution for x\in\mathbb{R}