What is the answer to |x^2+3x+2|+x+1=0 ?

The answer to |x^2+3x+2|+x+1=0 is x=-3\lor x=-1

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|x^2+3x+2|+x+1=0

x^{2} + 3 x + 2 + x + 1 = 0

x = - 3 or x = - 1

Solution steps

x^{2} + 3 x + 2 + x + 1 = 0

Find positive and negative intervals

x \leq - 2, - 2 < x < - 1, x \geq - 1

Solve the inequality for each interval

x = - 3 or No Solution or x = - 1

x = - 3 or x = - 1

x^{2} - 4 x + 2 = \frac{( 5 x - 4 )}{3}

∣ x ∣ - 2 ∣ x + 1 ∣ + 3 ∣ x + 2 ∣ = 0

x^{3} + x^{2} + x + 1 = x^{3} + 1 + x^{2} + x

∣ 2 x - 3 ∣ = ∣ 3 x + 5 ∣

2 ∣ x + 1 ∣^{2} - ∣ x + 1 ∣ = 3

What is the answer to |x^2+3x+2|+x+1=0 ?
The answer to |x^2+3x+2|+x+1=0 is x=-3\lor x=-1
Solve for x: |x^2+3x+2|+x+1=0
The solution is x=-3\lor x=-1