What is the answer to |2x-3|+|2x+1|+|2x+5|=12 ?

The answer to |2x-3|+|2x+1|+|2x+5|=12 is x=-5/2 \lor x= 3/2

Solve for x: |2x-3|+|2x+1|+|2x+5|=12

The solution is x=-5/2 \lor x= 3/2

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∣ 2 x - 3 ∣ + ∣ 2 x + 1 ∣ + ∣ 2 x + 5 ∣ = 12

x = - \frac{5}{2} or x = \frac{3}{2}

Decimal Notation

x = - 2.5, x = 1.5

Solution steps

∣ 2 x - 3 ∣ + ∣ 2 x + 1 ∣ + ∣ 2 x + 5 ∣ = 12

Find positive and negative intervals

x < - \frac{5}{2}, - \frac{5}{2} \leq x < - \frac{1}{2}, - \frac{1}{2} \leq x < \frac{3}{2}, x \geq \frac{3}{2}

Solve the inequality for each interval

No Solution or x = - \frac{5}{2} or x = \frac{3}{2}

x = - \frac{5}{2} or x = \frac{3}{2}

5 ∣ x + 3 ∣ - 1 = 6

∣ 2 x - 3 ∣ - x^{2} - 4 x + 3 = x^{2} - 2 x

x^{2} - x + ∣ x + 1 ∣ = 5

∣ x ∣ + ∣ y ∣ = 4

∣ x ∣ + x^{3} = 0

What is the answer to |2x-3|+|2x+1|+|2x+5|=12 ?
The answer to |2x-3|+|2x+1|+|2x+5|=12 is x=-5/2 \lor x= 3/2
Solve for x: |2x-3|+|2x+1|+|2x+5|=12
The solution is x=-5/2 \lor x= 3/2