What is the answer to |2x-3|-|x^2-4x+3|=|x^2-2x| ?

The answer to |2x-3|-|x^2-4x+3|=|x^2-2x| is 0<= x<= 1\lor 2<= x<= 3

Solve for x: |2x-3|-|x^2-4x+3|=|x^2-2x|

The solution is 0<= x<= 1\lor 2<= x<= 3

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The solution is 0<= x<= 1\lor 2<= x<= 3

∣ 2 x - 3 ∣ - x^{2} - 4 x + 3 = x^{2} - 2 x

0 \leq x \leq 1 or 2 \leq x \leq 3

Solution steps

∣ 2 x - 3 ∣ - x^{2} - 4 x + 3 = x^{2} - 2 x

Find positive and negative intervals

x \leq 0, 0 < x \leq 1, 1 < x < \frac{3}{2}, \frac{3}{2} \leq x < 2, 2 \leq x < 3, x \geq 3

Solve the inequality for each interval

x = 0 or 0 < x \leq 1 or No Solution or 2 \leq x < 3 or x = 3

Merge Overlapping Intervals

0 \leq x \leq 1 or 2 \leq x \leq 3

x^{2} - x + ∣ x + 1 ∣ = 5

∣ x ∣ + ∣ y ∣ = 4

∣ x ∣ + x^{3} = 0

(3 x - 2)^{2} - 5 ∣ 3 x - 2 ∣ - 6 = 0

x^{2} - 3 x + 2 = ∣ 2 x - 3 ∣

What is the answer to |2x-3|-|x^2-4x+3|=|x^2-2x| ?
The answer to |2x-3|-|x^2-4x+3|=|x^2-2x| is 0<= x<= 1\lor 2<= x<= 3
Solve for x: |2x-3|-|x^2-4x+3|=|x^2-2x|
The solution is 0<= x<= 1\lor 2<= x<= 3