What is the answer to |2x^2-4|=8x-6 ?

The answer to |2x^2-4|=8x-6 is x=1\lor x=2+sqrt(3)

Solve for x: |2x^2-4|=8x-6

The solution is x=1\lor x=2+sqrt(3)

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2 x^{2} - 4 = 8 x - 6

x = 1 or x = 2 + 3

Solution steps

2 x^{2} - 4 = 8 x - 6

Find positive and negative intervals

x \leq - 2, - 2 < x < 2, x \geq 2

Solve the inequality for each interval

No Solution or x = 1 or x = 2 + 3

x = 1 or x = 2 + 3

x^{2} - 5 x + 6 = 2 x - 3

\frac{( 4 w - 1 )}{6} = \frac{( 2 w )}{3} + \frac{1}{4}

∣ 2 x - 1 ∣ + x = 3

b ∣ 3 x + 6 ∣ - ∣ 2 x - 1 ∣ = 5

x^{2} - 1 = ∣ x + 3 ∣

What is the answer to |2x^2-4|=8x-6 ?
The answer to |2x^2-4|=8x-6 is x=1\lor x=2+sqrt(3)
Solve for x: |2x^2-4|=8x-6
The solution is x=1\lor x=2+sqrt(3)