What is the answer to log_{2}(x^2)=1 ?

The answer to log_{2}(x^2)=1 is x=sqrt(2),x=-sqrt(2)

Solve for x: log_{2}(x^2)=1

The solution is x=sqrt(2),x=-sqrt(2)

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lo g_{2} (x^{2}) = 1

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

lo g_{2} (x^{2}) = 1

Apply log rules

x^{2} = 2

Solve

x^{2} = 2 : x = 2, x = - 2

x = 2, x = - 2

lo g_{x} (8) + lo g_{x} (4) = 5

lo g_{10} ((x + 3)^{2}) - 2 = lo g_{10} (\frac{1}{( x ^{2} )})

a, lo g_{2} (a) - 3 lo g_{2} (b) = 2

lo g_{3} (2 x + 3) = 5

lo g_{2} (x - 2) + lo g_{2} (x + 1) = 2

What is the answer to log_{2}(x^2)=1 ?
The answer to log_{2}(x^2)=1 is x=sqrt(2),x=-sqrt(2)
Solve for x: log_{2}(x^2)=1
The solution is x=sqrt(2),x=-sqrt(2)