What is the answer to log_{10}(3x+1)=3 ?

The answer to log_{10}(3x+1)=3 is x=333

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log_{10}(3x+1)=3

lo g_{10} (3 x + 1) = 3

x = 333

Solution steps

lo g_{10} (3 x + 1) = 3

Apply log rules

3 x + 1 = 1000

Solve

3 x + 1 = 1000 : x = 333

x = 333

lo g_{2} (x) + lo g_{2} (x + 2) = 3

\frac{x}{lo g _{332} ( x ) + 1} = 15

lo g_{10} (81 x) = \frac{1}{4}

lo g_{10} (x) + lo g_{10} (x - 21) = 2

lo g_{3} (2 x + 1) + lo g_{3} (x + 8) = 3

What is the answer to log_{10}(3x+1)=3 ?
The answer to log_{10}(3x+1)=3 is x=333
Solve for x: log_{10}(3x+1)=3
The solution is x=333