What is the answer to log_{2}(x)+log_{2}(4)=log_{2}(20) ?

The answer to log_{2}(x)+log_{2}(4)=log_{2}(20) is x=5

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log_{2}(x)+log_{2}(4)=log_{2}(20)

lo g_{2} (x) + lo g_{2} (4) = lo g_{2} (20)

x = 5

Solution steps

lo g_{2} (x) + lo g_{2} (4) = lo g_{2} (20)

Move

lo g_{2} (4)

to the right side

lo g_{2} (x) = lo g_{2} (20) - lo g_{2} (4)

Apply log rules

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

lo g_{2} (x - 5) = lo g_{4} (x - 2) + lo g_{2} (2)

lo g_{2} (x + 3) = 4

lo g_{3} (lo g_{\frac{1}{2}} (x) - 3 \cdot lo g_{\frac{1}{2}} (x) + 5) = 2

lo g_{10} (x^{2}) - 1 = lo g_{10} (3 x)

lo g_{3} (4 - 4 x) = 1

What is the answer to log_{2}(x)+log_{2}(4)=log_{2}(20) ?
The answer to log_{2}(x)+log_{2}(4)=log_{2}(20) is x=5
Solve for x: log_{2}(x)+log_{2}(4)=log_{2}(20)
The solution is x=5