What is the answer to log_{10}(x^2)-1=log_{10}(3x) ?

The answer to log_{10}(x^2)-1=log_{10}(3x) is x=30

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(x^2)-1=log_{10}(3x)

lo g_{10} (x^{2}) - 1 = lo g_{10} (3 x)

x = 30

Solution steps

lo g_{10} (x^{2}) - 1 = lo g_{10} (3 x)

Apply log rules

x = 30

Verify Solutions:

x = 30

True

The solution is

x = 30

lo g_{3} (4 - 4 x) = 1

lo g_{4} (2 x - 32) = 5

lo g_{3} (x^{2} - x - 5) - lo g_{3} (x) = 1

lo g_{10} (98 + x^{2} - 12 x + 36) = 2

lo g_{10} (x - 2) + lo g_{10} (x + 2) = 2

What is the answer to log_{10}(x^2)-1=log_{10}(3x) ?
The answer to log_{10}(x^2)-1=log_{10}(3x) is x=30
Solve for x: log_{10}(x^2)-1=log_{10}(3x)
The solution is x=30