What is the answer to log_{4}(2x-32)=5 ?

The answer to log_{4}(2x-32)=5 is x=528

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log_{4}(2x-32)=5

lo g_{4} (2 x - 32) = 5

x = 528

Solution steps

lo g_{4} (2 x - 32) = 5

Apply log rules

2 x - 32 = 1024

Solve

2 x - 32 = 1024 : x = 528

x = 528

lo g_{3} (x^{2} - x - 5) - lo g_{3} (x) = 1

lo g_{10} (98 + x^{2} - 12 x + 36) = 2

lo g_{10} (x - 2) + lo g_{10} (x + 2) = 2

73 = 18 lo g_{10} (\frac{17.176}{x})

lo g_{10} (4 x + 6) = 2

What is the answer to log_{4}(2x-32)=5 ?
The answer to log_{4}(2x-32)=5 is x=528
Solve for x: log_{4}(2x-32)=5
The solution is x=528