What is the answer to log_{10}(98+sqrt(x^2-12x+36))=2 ?

The answer to log_{10}(98+sqrt(x^2-12x+36))=2 is x=8,x=4

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log_{10}(98+sqrt(x^2-12x+36))=2

lo g_{10} (98 + x^{2} - 12 x + 36) = 2

x = 8, x = 4

Solution steps

lo g_{10} (98 + x^{2} - 12 x + 36) = 2

Apply log rules

98 + x^{2} - 12 x + 36 = 100

Solve

98 + x^{2} - 12 x + 36 = 100 : x = 8, x = 4

x = 8, x = 4

lo g_{10} (x - 2) + lo g_{10} (x + 2) = 2

73 = 18 lo g_{10} (\frac{17.176}{x})

lo g_{10} (4 x + 6) = 2

lo g_{4} (8) + lo g_{4} (x + 3) - lo g_{4} (x - 1) = 2

lo g_{3} (3^{x} - 6) = x - 1

What is the answer to log_{10}(98+sqrt(x^2-12x+36))=2 ?
The answer to log_{10}(98+sqrt(x^2-12x+36))=2 is x=8,x=4
Solve for x: log_{10}(98+sqrt(x^2-12x+36))=2
The solution is x=8,x=4