What is the answer to ln(x-1)-ln(x+2)=ln(2) ?

The answer to ln(x-1)-ln(x+2)=ln(2) is No Solution for x\in\mathbb{R}

Solve for x: ln(x-1)-ln(x+2)=ln(2)

The solution is No Solution for x\in\mathbb{R}

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ln (x - 1) - ln (x + 2) = ln (2)

No Solution for x \in R

Solution steps

ln (x - 1) - ln (x + 2) = ln (2)

Add

ln (x + 2)

to both sides

ln (x - 1) - ln (x + 2) + ln (x + 2) = ln (2) + ln (x + 2)

Simplify

ln (x - 1) = ln (2) + ln (x + 2)

Apply log rules

x - 1 = 2 (x + 2)

Solve

x - 1 = 2 (x + 2) : x = - 5

x = - 5

Verify Solutions:

x = - 5

False

The solution is

No Solution for x \in R

a lo g_{2} (3.5) = lo g_{27} (- lo g_{22} (x))

x - 7 + lo g_{2} (x + 8) = - 5

ln (2) - ln (3 x + 4) + ln (4 - 3 x) = ln (2)

lo g_{2} (x^{3} + x + 1) = lo g_{2} (2 x^{2} + 1)

lo g_{10} (x + 3) - lo g_{10} (x - 3) = 1

What is the answer to ln(x-1)-ln(x+2)=ln(2) ?
The answer to ln(x-1)-ln(x+2)=ln(2) is No Solution for x\in\mathbb{R}
Solve for x: ln(x-1)-ln(x+2)=ln(2)
The solution is No Solution for x\in\mathbb{R}