What is the answer to log_{2}(x^3+x+1)=log_{2}(2x^2+1) ?

The answer to log_{2}(x^3+x+1)=log_{2}(2x^2+1) is x=0,x=1

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log_{2}(x^3+x+1)=log_{2}(2x^2+1)

lo g_{2} (x^{3} + x + 1) = lo g_{2} (2 x^{2} + 1)

x = 0, x = 1

Solution steps

lo g_{2} (x^{3} + x + 1) = lo g_{2} (2 x^{2} + 1)

Apply log rules

x^{3} + x + 1 = 2 x^{2} + 1

Solve

x^{3} + x + 1 = 2 x^{2} + 1 : x = 0, x = 1

x = 0, x = 1

Verify Solutions:

x = 0

True

, x = 1

True

The solutions are

x = 0, x = 1

lo g_{10} (x + 3) - lo g_{10} (x - 3) = 1

lo g_{10} (x^{2}) = 1.7482

2.3 lo g_{10} (\frac{t ^{1}}{t ^{2}}) = 0.69825

lo g_{10} (1 + x) = 1 + lo g_{10} (x)

ln (x + 1) = - 2

What is the answer to log_{2}(x^3+x+1)=log_{2}(2x^2+1) ?
The answer to log_{2}(x^3+x+1)=log_{2}(2x^2+1) is x=0,x=1
Solve for x: log_{2}(x^3+x+1)=log_{2}(2x^2+1)
The solution is x=0,x=1