What is the answer to ln(2)-ln(3x+4)+ln(4-3x)=ln(2) ?

The answer to ln(2)-ln(3x+4)+ln(4-3x)=ln(2) is x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln(2)-ln(3x+4)+ln(4-3x)=ln(2)

ln (2) - ln (3 x + 4) + ln (4 - 3 x) = ln (2)

x = 0

Solution steps

ln (2) - ln (3 x + 4) + ln (4 - 3 x) = ln (2)

Add

ln (3 x + 4)

to both sides

ln (2) - ln (3 x + 4) + ln (4 - 3 x) + ln (3 x + 4) = ln (2) + ln (3 x + 4)

Simplify

ln (2) + ln (4 - 3 x) = ln (2) + ln (3 x + 4)

Apply log rules

2 (4 - 3 x) = 2 (3 x + 4)

Solve

2 (4 - 3 x) = 2 (3 x + 4) : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

lo g_{2} (x^{3} + x + 1) = lo g_{2} (2 x^{2} + 1)

lo g_{10} (x + 3) - lo g_{10} (x - 3) = 1

lo g_{10} (x^{2}) = 1.7482

2.3 lo g_{10} (\frac{t ^{1}}{t ^{2}}) = 0.69825

lo g_{10} (1 + x) = 1 + lo g_{10} (x)

What is the answer to ln(2)-ln(3x+4)+ln(4-3x)=ln(2) ?
The answer to ln(2)-ln(3x+4)+ln(4-3x)=ln(2) is x=0
Solve for x: ln(2)-ln(3x+4)+ln(4-3x)=ln(2)
The solution is x=0