What is the answer to log_{10}(x)+log_{10}(7)=log_{10}(4) ?

The answer to log_{10}(x)+log_{10}(7)=log_{10}(4) is x= 4/7

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log_{10}(x)+log_{10}(7)=log_{10}(4)

lo g_{10} (x) + lo g_{10} (7) = lo g_{10} (4)

x = \frac{4}{7}

Decimal Notation

x = 0.57142 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (7) = lo g_{10} (4)

Move

lo g_{10} (7)

to the right side

lo g_{10} (x) = lo g_{10} (4) - lo g_{10} (7)

Apply log rules

x = \frac{4}{7}

Verify Solutions:

x = \frac{4}{7}

True

The solution is

x = \frac{4}{7}

lo g_{\frac{1}{2}} (x^{2} - 3) = lo g_{2} (x^{2})

u, lo g_{u} (\frac{15}{16}) = v

ln (x) = \frac{1}{2}

140 = 20 lo g_{10} (\frac{75000}{x})

x = ln (9 - x)

What is the answer to log_{10}(x)+log_{10}(7)=log_{10}(4) ?
The answer to log_{10}(x)+log_{10}(7)=log_{10}(4) is x= 4/7
Solve for x: log_{10}(x)+log_{10}(7)=log_{10}(4)
The solution is x= 4/7